Evaluate 7+77+777+7777........upto n terms
I am stuck on a step
I got this
how?
@ganeshie8
Shall i tell my approach i am stuck on a step
yea please
\[\frac{ 7 }{ 9 }\left\{ 9 +99 +999+....... \right\}\] \[\frac{ 7 }{ 9 }\left\{ (10-1) + (10^{2}-1)+..... \right\}\]
that looks great ! keep going
No i could have but i am stuck , i mean how should i procedd
group the exponents and 1's separately
and keep in mind that there are n terms
\[\frac{ 7 }{ 9 }\left\{ (10-1) + (10^{2}-1)+..... \right\}\] \[\frac{ 7 }{ 9 }\left\{ (10 + 10^2 + \cdots 10^n) - (1 + 1 + \cdots \text{n terms})\right\}\]
\[\frac{ 7 }{ 9 }\left\{ (10 + 10^2 + \cdots 10^n) - n\right\}\]
if they are similar we can write them as "one" Like n here?
1 + 1 = 2 1 + 1 + 1 = 3 1 + 1 + 1 + 1 = 4 1 + 1 + 1 + 1 + ... n times = n
now that can be done thanks a ton
can u plz help me after @ganeshie8
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