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Mathematics 21 Online
OpenStudy (anonymous):

helo please!!

OpenStudy (anonymous):

OpenStudy (anonymous):

Always remember that for a right triangle: |dw:1404250315431:dw| you use the trigonometric ratios(also known as SOH, CAH TOA): \(\LARGE tan\ \theta=\frac{opposite}{adjacent}, cos\ \theta=\frac{adjacent}{hypotenuse}, sin\ \theta=\frac{opposite}{hypotenuse}\)

OpenStudy (anonymous):

wow i really dont get this one like i cannot even guess the answer

OpenStudy (anonymous):

\(\LARGE \theta\) represents any angle (A or C, since B is already the 90°). you can apply the trig ratios on each choices to find which ratio will satisfy \(\LARGE \frac{a}{c}\). |dw:1404250760917:dw| As you can see, \(\LARGE \frac{a}{c}\) is same as \(\LARGE \frac{opposite}{adjacent}\), so it means that it should be a \(tangent\) ratio. You just have to find out what angle will satisfy \(\LARGE tan\ \theta=\frac{opposite}{adjacent}=\frac{a}{c}\). Look at the diagram, which angle is the opposite of side \(a\)?

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