write the equation in slope-intercept form and identify the slope and y intercept 7x+6y=17 slope intercept form is y=? the slope is ? y-intercept is?
if you solve that for "y", what would you get?
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well recall to solve linear equations you isolate the variable on one side so to isolate "y" on the left-hand-side subtract "7x" to both sides then divide by "6" both sides what would you get on that?
so would that be 7x+6y-7x=17-7?
well 7x to both sides you're subtracting it from the left, but on the right side you're only subtracting 7
so 17-7x?
so would it be 6y=10x
on the right, yes, thus \(\bf \cancel{ 7x }+6y\cancel{ -7x }=17-7x\) now if you divide 6 on both?
will it be 4? cause its not dividing with 10 so I just added 17+7 and got 24
\(\large { \cancel{ 7x }+6y\cancel{ -7x }=17-7x\implies 6y=17-7x \\ \quad \\ \cfrac{\cancel{ 6 }y}{\cancel{ 6 }}=\cfrac{17-7x}{6}\implies y=\cfrac{17-7x}{6} \\ \quad \\ slope-intercept\ form\to y=mx+b\qquad thus \\ \quad \\ y=\cfrac{17-7x}{6}\implies y=\cfrac{17}{6}-\cfrac{7x}{6}\implies y=-\cfrac{7x}{6}+\cfrac{17}{6} \\ \quad \\ \implies \begin{array}{llll} y=&{\color{purple}{ -\cfrac{7}{6}}}x&{\color{blue}{ +\cfrac{17}{6}}}\\ &\quad \uparrow &\quad \uparrow \\ &{\color{purple}{ slope}}&{\color{blue}{ y-intercept}} \end{array} }\)
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