Question

related rates problem
just need someone to double check my set up and solution

Answer 1

I will answer this

Answer 2

I mean check this...

Answer 3

Air is leaking out of an inflated balloon in the shape of a sphere at a rate of 230 pi cubic centimeters per minute. At the instant when the radius is 4 centimeters, what is the rate of change of the radius of the balloon?

Answer 4

thanks

Answer 5

I used \[V=\frac{ 4 }{ 3 }\pi r^3\]

Answer 6

\[\frac{ dv }{ dt}=4\pi r^2 \frac{ dr }{ dt }\]

Answer 7

Volume =4/3 pi r cubed...

Answer 8

so...

Answer 9

r = 4 dv/dt =230 pi

Answer 10

my solution is dr/dr = 3.59375 cm/sec

Answer 11

Ok let me do the math myself..

Answer 12

Process seems correct.

Answer 13

I got t he same answer.

Answer 14

but in cm/min

Answer 15

thanks I haven't done related rates in a while. yes you are correct cm/min

Answer 16

Ok so since r = 4 dv/dt =230 pi... dr/dr= Yes i got 3.59375 cm/min

Answer 17

oh and its cm/min

Answer 18

thank you for checking it. I knew I could not have done the whole thing correct.

Answer 19

No problem!