If 33.7 grams of LiOH dissolve in enough water to make a 231-gram solution, what is the concentration in percent by mass? 14.6% LiOH 12.7% LiOH 8.73% LiOH 6.85% LiOH can anyone explain how to solve this?
\(\huge\text{Concentration in % mass=}\)\(\huge\frac{mass~of~solute}{mass~of~solvent}*100\)
= \(\huge\frac{33.7}{231}*100\) = 14.588 \(\approx\) 14.6%
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thanks! could you help me out with a few more?
yeah sure..post the questions as new one.
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okay ill tag you in them
sure \(\huge\color{green}{ت}\)
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