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Chemistry 20 Online
OpenStudy (anonymous):

If 33.7 grams of LiOH dissolve in enough water to make a 231-gram solution, what is the concentration in percent by mass? 14.6% LiOH 12.7% LiOH 8.73% LiOH 6.85% LiOH can anyone explain how to solve this?

OpenStudy (abhisar):

\(\huge\text{Concentration in % mass=}\)\(\huge\frac{mass~of~solute}{mass~of~solvent}*100\)

OpenStudy (abhisar):

= \(\huge\frac{33.7}{231}*100\) = 14.588 \(\approx\) 14.6%

OpenStudy (abhisar):

\(\Huge{\color{red}{\bigstar}\color{blue}{\bigstar}\color{green}{\bigstar}\color{yellow}{\bigstar}\color{orange}{\bigstar}\color{red}{\bigstar}\color{blue}{\bigstar}\color{green}{\bigstar}\color{yellow}{\bigstar}\color{orange}{\bigstar}\color{red}{\bigstar}\color{blue}{\bigstar}\color{green}{\bigstar}\color{yellow}{\bigstar}}\\\color{white}{.}\\\Huge\color{blue}{\mathfrak{~~~~Welcome~to~OpenStudy!~\ddot\smile}}\\\color{white}{.}\\\\\Huge{\color{red}{\bigstar}\color{blue}{\bigstar}\color{green}{\bigstar}\color{yellow}{\bigstar}\color{orange}{\bigstar}\color{red}{\bigstar}\color{blue}{\bigstar}\color{green}{\bigstar}\color{yellow}{\bigstar}\color{orange}{\bigstar}\color{red}{\bigstar}\color{blue}{\bigstar}\color{green}{\bigstar}\color{yellow}{\bigstar}}\)

OpenStudy (abhisar):

Did you know you can give medals to people who help you with questions? Just click the \(\color{blue}{\text{blue "best response" button}}\) to show appreciation for the people who help you.

OpenStudy (anonymous):

thanks! could you help me out with a few more?

OpenStudy (abhisar):

yeah sure..post the questions as new one.

OpenStudy (abhisar):

\(\color{red}{\huge\bigstar}\huge\text{You're Most Welcome! }\color{red}\bigstar\) \(~~~~~~~~~~~~~~~~~~~~~~~~~~~\color{green}{\huge\ddot\smile}\color{blue}{\huge\ddot\smile}\color{pink}{\huge\ddot\smile}\color{red}{\huge\ddot\smile}\color{yellow}{\huge\ddot\smile}\)

OpenStudy (anonymous):

okay ill tag you in them

OpenStudy (abhisar):

sure \(\huge\color{green}{ت}\)

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