If .29 g of aluminum reacts with excess sulfur, what mass of aluminum sulfide can form?
To start with, Aluminium sulfide is Al\(_2\)S\(_3\)
2Al + 3S ---> Al2S3 first find mole of Al because you are given mass of Al mole= mass/Molecular mass Molecular mass of 2Al you can find from periodic table (do consider the coefficient, its 2 that means there are 2 Al atoms) and get the mole next look at the ratio between Al and Al2S3 (look at coefficients) you can see that its 2:1 that means 2--- the mole you just got 1 ---- X mole of Al2S3 so find X= mole that you just got/ 2 now you have the mole use formula mole= mass/ Molecular mass and calculate for mass mass= mole * Molecular mass mole - you just got it Molecular mass of Al2S3 you can find from periodic table Hope it helps :)
Join our real-time social learning platform and learn together with your friends!