Awarding Medal. What is the value of the expression begin square root symbol a squared plus b squared minus four end square root symbol minus b squared when a = 6 and b = 2?

Question

anonymous · Answer

A. 
-2

B. 0

C. 2

D. 4

the_fizicx99 · Answer

Ehhm hopefully I read it correctly, lol :3

$\ \sf \sqrt{a^2 + b^2 - 4} -b^2 $

If $\ \sf \color{blue}{B} = 2$ and $\ \sf \color{red}{A} = 6 $

Then, $\ \sf \sqrt{(\color{red}{6})^2 + (\color{blue}{2})^2 - 4}$ - $\ \sf (\color{blue}{2})^2 \implies \sqrt{36 + 4 - 4} - 4 \implies \sqrt{36} - 4 = 6 - 4 = 2 $

the_fizicx99 · Answer

There was actually an even faster method of doing this, you could have cancel out the square and taken the square root of 4 and kept the negative sign.

(6 + 2 - 2) - 4 = 6 - 4 = 2

anonymous · Answer

Thank You Very Much I'm So Grateful. <3