The probability of Dawn reading before going to bed is 5/6. The probability of Dawn brushing her teeth before going to bed is 6/7. The probability of Dawn watching TV before going to bed is 1/5. What is the probability that she will do all three activities before going to bed?

Question

amistre64 · Answer

does any one activity affect the probability of the other?

anonymous · Answer

Yes, i think

amistre64 · Answer

i dont think they have any affect on each other, i believe that they are independant events.

what in your material suggests a way that we can find P(A and B and C)

anonymous · Answer

Add them?

amistre64 · Answer

almost ... adding is associated with the word 'or'.  if the events are independant, and we want to 'and; them; we can simply multiply them togther.

amistre64 · Answer

so, the way i see it, we can simply do this$$P(A\cap B\cap C)=\frac{5}{6}*\frac{6}{7}*\frac{1}{5}$$

anonymous · Answer

How would i multiply the fractions together? Would I cross multiply?

amistre64 · Answer

no, fractions are just multiplied straight across.   cross multiplication is a memory device used when there are fractions seperated by an = sign.  none of our fractions are seperated by an = sign in this

anonymous · Answer

Okay. Soooo

amistre64 · Answer

soo, thats as far as im willing to take you on this.  your question was on probability, not mutliplication of fractions.

anonymous · Answer

It would be 1/7?

amistre64 · Answer

it would be yes :)

anonymous · Answer

A bag contains 3 red marbles, 4 blue marbles, and 5 white marbles. What is the probability of pulling out a white marble, and then a blue marble if none are replaced?