Question

Giving medals!

Given: 3x + y = 1.

Solve for y.


y = -3x + 1
y = -3x - 1
y = 3x - 1

Answer 1

set the equation = to y

Answer 2

then solve it

Answer 3

its a

Answer 4

You would start out by subtracting y from both sides

Answer 5

You are supposed to help not just give the answers

Answer 6

subtract Y from what!

Answer 7

acually you would subtract the 3x @CookieMonsta22

Answer 8

Oh yeah that would make it easier! My bad :/

Answer 9

all you have to do is subtract 3x and since that is not one of the choices add -3x because its basically the same thing

Answer 10

once you do that it would be y by itself

Answer 11

Thanks :)

Answer 12

Then you would simplify

Answer 13

im terrible with this stuff. i got another one anyone want to help?
Given: x + 2y = -6.

Solve for y.

Answer 14

the answer choices dont look like you would simplify

Answer 15

that one you'd still set it = to y and get 2y=-x-6

Answer 16

you would subtract the x first and then divide by 2

Answer 17

Not for this question but if you were to solve for y then you would continue by simplifying.

Answer 18

that is not one of the answers its all a fraction like y= x-6 over 2

Answer 19

the answer is -6 -x over 2

Answer 20

ohh well cool. thanks

Answer 21

you're welcome

Answer 22

\[y=\frac{ -x-6 }{ 2 }\]

Answer 23

this ones a bit harder :

Given: x + y = 6.

If x {-15, -6, -1}, then which of the following sets of ordered pairs are solutions?


{(-15, -21), (-6, -12), (-1, -7)}
{(-15, 21), (-6, 12), (-1, 7)}
{(-15, 21), (-6, 12), (-1, -7)}

Answer 24

how did you get the pic on here?

Answer 25

it has an equation option

Answer 26

click equation by the chat and type it accordenly

Answer 27

that one is easy just plug in the x's and solve for the y's @scoob

Answer 28

ohhh thats cool good to know.

Answer 29

i got it!

Answer 30

cool

Answer 31

If the ordinate equals the abscissa and x {-3, 0, 12}, which of the following sets of ordered pairs satisfies the given conditions?


{(3, -3), (0, 0), (-12, 12)}
{(-3, 3), (0, 0), (12, -12)}
{(-3, -3), (0, 0), (12, 12)}

Answer 32

isnt the abscissa the same as x?

Answer 33

yes i would think so