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Mathematics 27 Online
OpenStudy (anonymous):

rq2 + 3qr + r2 for r = 5 and q = 2

OpenStudy (anonymous):

Just plug it in like this; (5)(2)+3(2)(5)+5(2)

OpenStudy (texaschic101):

rq^2 + 3qr + r^2 -- r = 5 and q = 2 now we sub 5(2^2) + 3(2)(5) + 5^2 5(4) + 6(5) + 25 20 + 30 + 25 50 + 25 75

OpenStudy (texaschic101):

I hope the 2's are powers....like 2^2, instead of just multiplying by 2

OpenStudy (anonymous):

They are!

OpenStudy (anonymous):

thank you so much I was stuck for hours

OpenStudy (texaschic101):

glad to help :)

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