Please help me this, estimate the value of the limit lim x->0 (1+x)^1/x
\[\lim_{x \rightarrow 0} (1+x)^{1/x}\] is the answer 0?
We can let \(\large L = (1+x)^{1/x} = e^{\ln L}\), So \(\Large \displaystyle \lim_{x\rightarrow0}L = \lim_{x\rightarrow0}e^{\ln L} = \lim_{x\rightarrow0}e^{\frac{\ln(1+x)}{x}} =e^{\lim_{x\rightarrow 0}\frac{\ln(1+x)}{x}}\) After direct substitution, you will get indeterminate form: 0/0, so apply L'Hopital's rule. I'm sure you can handle it on your own afterward. Hope this helps!
Does this help? Need me to clarify more? @gogonhan
can you please show more work, i dont get it... Sorry I just got Caculous this morning... so a lot of confusing...
which part are you confused with?
okie... I got it... just read the book... thank you :D
no problem!
Join our real-time social learning platform and learn together with your friends!