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Mathematics 10 Online
OpenStudy (anonymous):

Find x. Round to the nearest degree.

OpenStudy (anonymous):

OpenStudy (anonymous):

Know your trig ratios?

OpenStudy (anonymous):

like the 30 60 90 rule and all that?

jimthompson5910 (jim_thompson5910):

use the law of sines http://www.mathsisfun.com/algebra/trig-sine-law.html

OpenStudy (anonymous):

ok!

OpenStudy (jdoe0001):

is that supposed to be a right triangle?

OpenStudy (anonymous):

^ That's what I thought haha

OpenStudy (jdoe0001):

sorta ambiguous =)

OpenStudy (anonymous):

39/sin(x) ?

jimthompson5910 (jim_thompson5910):

and that's equal to what?

OpenStudy (anonymous):

and idk if it is a right trianlge this is all the information i was given

OpenStudy (anonymous):

um b/sinb?

jimthompson5910 (jim_thompson5910):

39/sin(x) is on the right track, but it's only half of what you need

jimthompson5910 (jim_thompson5910):

oh I'm not thinking, the law of sines won't work here

jimthompson5910 (jim_thompson5910):

but the law of cosines will

OpenStudy (anonymous):

oh ok!

jimthompson5910 (jim_thompson5910):

|dw:1404337558278:dw|

jimthompson5910 (jim_thompson5910):

law of cosines b^2 = a^2 + c^2 - 2ac*cos(B) 39^2 = 59^2 + 36^2 - 2*59*36*cos(x) solve for x

OpenStudy (anonymous):

ok im at 1521=529cos(x) is this correct so far

jimthompson5910 (jim_thompson5910):

the left is right, but the right side is not

jimthompson5910 (jim_thompson5910):

strange as that sounds...

jimthompson5910 (jim_thompson5910):

you cannot go from 59^2 + 36^2 - 2*59*36*cos(x) to 529*cos(x)

OpenStudy (anonymous):

oh whoops so how do you multiple and subtract all that

jimthompson5910 (jim_thompson5910):

if it helps, think of cos(x) as a variable, say z so 59^2 + 36^2 - 2*59*36*cos(x) is really 59^2 + 36^2 - 2*59*36*z

OpenStudy (anonymous):

3481+1296-4248z 4777-4248z 529z i keep getting this?

jimthompson5910 (jim_thompson5910):

the jump from 4777-4248z to 529z is not a valid move

jimthompson5910 (jim_thompson5910):

4777 and -4248z are NOT like or common terms. You cannot combine them

OpenStudy (anonymous):

ooh!! so i have to multiple it by z first

jimthompson5910 (jim_thompson5910):

the goal now is to solve for z (which essentially isolates cos(x))

OpenStudy (anonymous):

when i did 4248cos in my calculator it came out as .3090 and like so on

jimthompson5910 (jim_thompson5910):

Here's what you should have 39^2 = 59^2 + 36^2 - 2*59*36*cos(x) 39^2 = 59^2 + 36^2 - 2*59*36*z 1521 = 3481+1296-4248*z 1521 = 4777 - 4248*z 1521 - 4777 = -4248*z -3256 = -4248*z -4248*z = -3256 z = -3256/(-4248) z = 0.766478 cos(x) = 0.766478 x = ???

OpenStudy (anonymous):

oh you had to get it alone do i have to now move x over? or do i put it in my calculator like that?

jimthompson5910 (jim_thompson5910):

what function undoes cosine?

OpenStudy (anonymous):

divison?

jimthompson5910 (jim_thompson5910):

no it's inverse cosine, aka arccosine

jimthompson5910 (jim_thompson5910):

you apply the arccosine to both sides to isolate x

OpenStudy (anonymous):

oh i never learned about that what is it

jimthompson5910 (jim_thompson5910):

ok have a look at this page http://www.themathpage.com/atrig/inverseTrig.htm and tell me what you think

OpenStudy (anonymous):

so you would like "switch" the x and .76647

jimthompson5910 (jim_thompson5910):

no

jimthompson5910 (jim_thompson5910):

we know that cos(60) = 1/2 correct?

OpenStudy (anonymous):

i guess

jimthompson5910 (jim_thompson5910):

so let's say we had cos(x) = 1/2 and we had no idea that x was 60

jimthompson5910 (jim_thompson5910):

we would apply the arccosine function to both sides to get cos(x) = 1/2 arccos(cos(x)) = arccos(1/2) x = 60

jimthompson5910 (jim_thompson5910):

what kind of calculator do you have?

OpenStudy (anonymous):

whatever one is on the iphone

jimthompson5910 (jim_thompson5910):

does that have inverse trig functions on it?

OpenStudy (anonymous):

no i dont think so

jimthompson5910 (jim_thompson5910):

ok I recommend you use an online calculator wolfram alpha and google are two good calculators

jimthompson5910 (jim_thompson5910):

if you were to type "arccos(0.766478) in degrees" without quotes into google, you'd get your answer (make sure to round of course)

jimthompson5910 (jim_thompson5910):

sorry I meant to say "arccosine(0.766478) in degrees" enter that without quotes

OpenStudy (anonymous):

so it would rounf to 40?

jimthompson5910 (jim_thompson5910):

correct

OpenStudy (anonymous):

It was thank you so much for your time!

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