Find x. Round to the nearest degree.
Know your trig ratios?
like the 30 60 90 rule and all that?
use the law of sines http://www.mathsisfun.com/algebra/trig-sine-law.html
ok!
is that supposed to be a right triangle?
^ That's what I thought haha
sorta ambiguous =)
39/sin(x) ?
and that's equal to what?
and idk if it is a right trianlge this is all the information i was given
um b/sinb?
39/sin(x) is on the right track, but it's only half of what you need
oh I'm not thinking, the law of sines won't work here
but the law of cosines will
oh ok!
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law of cosines b^2 = a^2 + c^2 - 2ac*cos(B) 39^2 = 59^2 + 36^2 - 2*59*36*cos(x) solve for x
ok im at 1521=529cos(x) is this correct so far
the left is right, but the right side is not
strange as that sounds...
you cannot go from 59^2 + 36^2 - 2*59*36*cos(x) to 529*cos(x)
oh whoops so how do you multiple and subtract all that
if it helps, think of cos(x) as a variable, say z so 59^2 + 36^2 - 2*59*36*cos(x) is really 59^2 + 36^2 - 2*59*36*z
3481+1296-4248z 4777-4248z 529z i keep getting this?
the jump from 4777-4248z to 529z is not a valid move
4777 and -4248z are NOT like or common terms. You cannot combine them
ooh!! so i have to multiple it by z first
the goal now is to solve for z (which essentially isolates cos(x))
when i did 4248cos in my calculator it came out as .3090 and like so on
Here's what you should have 39^2 = 59^2 + 36^2 - 2*59*36*cos(x) 39^2 = 59^2 + 36^2 - 2*59*36*z 1521 = 3481+1296-4248*z 1521 = 4777 - 4248*z 1521 - 4777 = -4248*z -3256 = -4248*z -4248*z = -3256 z = -3256/(-4248) z = 0.766478 cos(x) = 0.766478 x = ???
oh you had to get it alone do i have to now move x over? or do i put it in my calculator like that?
what function undoes cosine?
divison?
no it's inverse cosine, aka arccosine
you apply the arccosine to both sides to isolate x
oh i never learned about that what is it
ok have a look at this page http://www.themathpage.com/atrig/inverseTrig.htm and tell me what you think
so you would like "switch" the x and .76647
no
we know that cos(60) = 1/2 correct?
i guess
so let's say we had cos(x) = 1/2 and we had no idea that x was 60
we would apply the arccosine function to both sides to get cos(x) = 1/2 arccos(cos(x)) = arccos(1/2) x = 60
what kind of calculator do you have?
whatever one is on the iphone
does that have inverse trig functions on it?
no i dont think so
ok I recommend you use an online calculator wolfram alpha and google are two good calculators
if you were to type "arccos(0.766478) in degrees" without quotes into google, you'd get your answer (make sure to round of course)
sorry I meant to say "arccosine(0.766478) in degrees" enter that without quotes
so it would rounf to 40?
correct
It was thank you so much for your time!
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