Question

Solve the following system of equations:

2x + 4y - 3z = -7
3x + y + 4z = -12
x + 3y + 4z = 4

Answer 1

http://openstudy.com/users/iambatman#/updates/53b319b9e4b072c759d78d8e Scroll down.

Answer 2

@TerrelD99

Answer 3

@iambatman where to

Answer 4

1. x= 1/2(-4y+3z-7)

Answer 5

2. x= -y/3 - 4(z+3)/3

Answer 6

its asks to solve the x y and z

Answer 7

Oh alright go to this webiste and copy and paste your quetions in their http://www.wolframalpha.com/widget/widgetPopup.jsp?p=v&id=7953c4ea52a4873d32cc72052f3dcb10&title=Solve%20for%20X%20Calculator&theme=blue&i0=2x%20%2B%204y%20-%203z%20%3D%20-7%20&podSelect=&includepodid=Input&includepodid=Result&podstate=Result__Show%20steps&showAssumptions=1&showWarnings=1

Answer 8

i would do this using matrices, personally...

Answer 9

huh

Answer 10

@marliileon Did you figure this out, I'm sure you don't know about matrices, does it ask you to use a specific method?

Answer 11

i just plugged in a bunch of numbers it took forever but i got it

Answer 12

Oh ok, well if you have another question, just tag me I'll explain how to do it.

Answer 13

Using elimination/ substitution what ever you like.

Answer 14

okay thankx

Answer 15

Or I guess I can show you this one?

Answer 16

Did you look at the link I sent you earlier though? You just had to scroll down. Or wait a sec.

Answer 17

i did but i couldnt find anything it sent me to ur page

Answer 18

You had to scroll down but here,

http://puu.sh/9Uw94/6b01b15e05.png
http://puu.sh/9Uw9J/7647abffce.png

Answer 19

That's an example I did since a lot of people were asking for it.

Answer 20

Actually, no I would use substitution and elimination to do this one...matrices are a pain in the butt...

Answer 21

lol that wasnt it
it ended up being (-6, 2, 1)

Answer 22

No, I'm saying that's just an example I did, not your problem. You should read it, will show you the steps and how to do other problems.

Answer 23

Work to eliminate the z's between the first and second equations, and then work to eliminate the z's between the second and third equations, and then use the results from those, the 2 new equations in x and y only, and use those to solve for x or y. when you find x or y, sub that value back into your 2-variable equation to solve for the other variable, then when you find the values for both x and y, sub those back into one of your 3-variable equations and solve for z. It's very simple, actually!