Picture is attached below. PLEASE show me how to solve this.
who the flutter chose colors like this? it hurts my eyes...
use calculator and it is solved shift cos then divide by 2 and so on
LOL! @geerky42 I was thinking the same thing! xD
i dont know if it is correct but i think that the answer is 0.948683...
You need to actually plot this using the cosine identity. Do you know how to do that?
ya i think the program wants me to use this equation
BTW the sin of an angle is not represented as .948683. You need it as a fraction. In Q2 this is what the angle looks like:
|dw:1404352338662:dw|
when you solve for x you are solving for the side opposite the angle, which is what you need when you find the sin of the angle. Sin theta = side opposite / hypotenuse.
Solve for x using Pythagorean's Theorem, you get \[x ^{2}+(-4)^{2}=(5)^{2}\]which equals\[x ^{2}+16=25\]
\[x ^{2}=25-16\]\[x ^{2}=9\]\[x=3\]
And it is a positive because y is positive in Q2. So now you have this angle with these sides:|dw:1404352583736:dw|
Now that you have sin = 3/5, you have to find \[\sin \frac{ \theta }{ 2 }=\sin \frac{ \frac{ 3 }{ 5 } }{ 2 }\]
\[\sin \frac{ \theta }{ 2 }=\frac{ 3 }{ 10 }\]
Thanks i get it now!
Half angles...poop.
Ok so i put 3/10 in for the answer and it didnt work?
That's because this is a half angle problem...
Working on it now...
OK
I'm working it using the formula which I completely overlooked while I was typing before. Let me get a handle on it for a sec. I'll come up with the answer then tell you then explain it.
Ok
Big fat duh! I was making this WAYYYYYYY harder than it had to be! That's why it took me so long! Here we go...
ready
Using your formula for the half angle, this is what you do: you replace the "cos theta" with -4/5:
\[\pm \sqrt{\frac{ 1-(\frac{ -4 }{ 5 }) }{ 2 }}\]
Getting a common denominator we have:
|dw:1404354222147:dw|
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