I just had a quick question on capacitors and how they are connected in series:

The question that I am asked is what is the equivalent capacitance of the combination of these four capacitors in series:

(I'll post up a picture in a bit)

Question

I just had a quick question on capacitors and how they are connected in series: 

The question that I am asked is what is the equivalent capacitance of the combination of these four capacitors in series:

(I'll post up a picture in a bit)

anonymous · Answer

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anonymous · Answer

So I know that for a series like this it would just be 1/C+ 1/C+1/C+1/C, correct? But it is not accepting my answer as correct. I'm very confused! 

Thank you in advanced!

kropot72 · Answer

$$\frac{1}{C _{equivalent}}=\frac{1}{C }+\frac{1}{C}+\frac{1}{C }+\frac{1}{C }$$
$$\frac{1}{C _{equivalent}}=\frac{4}{C}$$
$$C _{equivalent}=\frac{C}{4}$$

anonymous · Answer

Oh my god that was correct! Thank you so much!! I was just wracking my brain on this all day. THank you!!

kropot72 · Answer

You're welcome :)