Question

@jim_thompson5910
Math is a pain..

Answer 1

It's confusing me..

Answer 2

( h o h)(10)

is the same as

h( h(10) )

Answer 3

h(10) = ??

Answer 4

so I would do
6-x (6-x (10) )

h= 6-x so h(10) means 6-x(10) ?
If so, that means

6-x (10)= 6-10x

Answer 5

h(x) = 6 - x

h(10) = 6 - 10

h(10) = ???

Answer 6

= -4 ?
@jim_thompson5910

Answer 7

h(10) = -4

Answer 8

h( h(10) ) = h( -4 ) = ???

Answer 9

so confused @jim_thompson5910 ...

Answer 10

you saw how I got h(10) right?

Answer 11

@jim_thompson5910 It's a function of a function, a composite function, the right answer is 10

Answer 12

\[(h\cdot h)=h[h(x)]\]if\[h(x)=6-x\]then\[h[h(x)]=6-h(x)\]replacing x by 10\[h(x)=6-10=-4\]replacing this new value at the composite function\[h[h(10)]=6-h(10)=6-(-4)=\boxed{10}\]therefore\[\boxed{\boxed{(h\cdot h)=10}}\]

Answer 13

Thank you! ^

Answer 14

really Great Explanation ! :DD

Answer 15

You're welcome ;)