Question

Condensing Logarithms

Answer 1

the equation is number 20 http://www.luminpdf.com/files/1476787/Unit%207%20Summer%20Work.pdf

Answer 2

The link looks broken.

Answer 3

Link not working

Answer 4

Same denominator, add the numerators first.

Answer 5

\[\log_{9}uvw \] ?

Answer 6

over 3

Answer 7

That's right. Now, you have\[\large \dfrac{\log_9 uvw}{3} = \dfrac{\log_9 uvw}{\log_9 {9^3}}= \log_{9^3}{uvw}\]Do you follow?

Answer 8

thanks

Answer 9

that answer isn't one of the options

Answer 10

Never mind that one. I have a better method.\[\large\dfrac{ \log_9{uvw}}{3} = \dfrac{1}{3}\log_9(uvw) = \log_9{\left(\left(uvw\right)^{1/3}\right)}\]

Answer 11

so the answer is \[\log_{9} \sqrt[3]{wvu}\]

Answer 12

indeed.

Answer 13

Thank you

Answer 14

No problem.