estimating slope of a secant line using a table of values
Well, I thought if I estimated the derivative using the point on either side they would match.
when I used the slope formula at x = 1 I got -4 and 1 I thought this would help me determine if the function is increasing or decreasing when I used the slope formula at x=0 I got -1/3 and -4 that told me the f(x) is decreasing at x=0 since the slopes are negative I can't do this at x=1 what I am doing incorrect?
when I graph the points it looks like x=1 is a minimum but am I correct in stating that
sorry I was helping someone with a problem. I figure I could help others while I wait
well looks like x=1 is a min x=4 is a max x=-6 is a min
I am just concluding that based on the graph, I plotted them on my graphing calculator.
For \(x = 0\) : slope of secant line = \(\dfrac{f(1) - f(-3)}{1-(-3)} \)
ok so I am doing this incorrect. I was using the point on the side of the given point. I was calculating 2 slopes. I should have been just doing one slope
ok let me redo this
okiee
@ganeshie8 when you have time I have a question
sure ask precal :)
ok I don't know the purpose of this exercise at all. when I graph these points, I determine that 1,4,6 were mins or max when I calculated the slope of the secant line I got x=0, x=1, x=4 decreasing and x=6 increasing
so I know I am overlooking something
i see, but we cannot say 1,4,6 are mins/max cuz we don't have the graph - we just have few points and we don't know how the graph behaves at other points
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