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Algebra 26 Online
OpenStudy (anonymous):

Find the number that belongs under the readical

OpenStudy (anonymous):

\[\sqrt{\frac{ }{ 6 }}=2\]

OpenStudy (anonymous):

I think 24 would work here. 24/6=4 square root of 4 is 2

OpenStudy (anonymous):

that was wrong

OpenStudy (anonymous):

What are the options?

OpenStudy (anonymous):

there are none

OpenStudy (anonymous):

Well 2 squared equals 4, so any number that is divided by 6 to equal 4 should work so I'm not sure what to tell ya

OpenStudy (anonymous):

\[\sqrt{\frac{ 144 }{ -3}}=\]

OpenStudy (anonymous):

I need help

OpenStudy (anonymous):

\[\sqrt{\frac{ 144 }{ -3 }}=\frac{ \sqrt{144} }{ \sqrt{-3}}=\frac{ 12 }{ \sqrt{-3}}\] \[\frac{ 12 }{ \sqrt{-3} }=\frac{ 12 }{ \sqrt{i ^{2}3}}=\frac{ 12 }{ i \sqrt{3} }=\frac{ 12\sqrt{3} }{ i }\]

OpenStudy (anonymous):

thanks

OpenStudy (anonymous):

yw

OpenStudy (anonymous):

find the missing factor \[8=8^{4}*blank\]

OpenStudy (anonymous):

\[8=8^{4}*x\]\[\frac{ 8 }{ 8^{4} }=x\]\[8^{1}*8^{-4}=x\]\[8^{(1-4)}=x\]\[8^{-3}=x\]

OpenStudy (anonymous):

\[9^{2}*9^{-6}\]

OpenStudy (anonymous):

OK this is the last one I'm going to do for you. \[9^{2}*9^{-6}=9^{(2-6)}=9^{-4}\]

OpenStudy (anonymous):

\[4^{4}=blank*4^{4}\]

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