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Algebra
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OpenStudy (anonymous):
Find the number that belongs under the readical
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OpenStudy (anonymous):
\[\sqrt{\frac{ }{ 6 }}=2\]
OpenStudy (anonymous):
I think 24 would work here.
24/6=4
square root of 4 is 2
OpenStudy (anonymous):
that was wrong
OpenStudy (anonymous):
What are the options?
OpenStudy (anonymous):
there are none
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OpenStudy (anonymous):
Well 2 squared equals 4, so any number that is divided by 6 to equal 4 should work so I'm not sure what to tell ya
OpenStudy (anonymous):
\[\sqrt{\frac{ 144 }{ -3}}=\]
OpenStudy (anonymous):
I need help
OpenStudy (anonymous):
\[\sqrt{\frac{ 144 }{ -3 }}=\frac{ \sqrt{144} }{ \sqrt{-3}}=\frac{ 12 }{ \sqrt{-3}}\]
\[\frac{ 12 }{ \sqrt{-3} }=\frac{ 12 }{ \sqrt{i ^{2}3}}=\frac{ 12 }{ i \sqrt{3} }=\frac{ 12\sqrt{3} }{ i }\]
OpenStudy (anonymous):
thanks
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OpenStudy (anonymous):
yw
OpenStudy (anonymous):
find the missing factor \[8=8^{4}*blank\]
OpenStudy (anonymous):
\[8=8^{4}*x\]\[\frac{ 8 }{ 8^{4} }=x\]\[8^{1}*8^{-4}=x\]\[8^{(1-4)}=x\]\[8^{-3}=x\]
OpenStudy (anonymous):
\[9^{2}*9^{-6}\]
OpenStudy (anonymous):
OK this is the last one I'm going to do for you.
\[9^{2}*9^{-6}=9^{(2-6)}=9^{-4}\]
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OpenStudy (anonymous):
\[4^{4}=blank*4^{4}\]
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