Let f(x) = 7x - 13. Find f-1(x). I'll medal
To find the inverse: Replace f(x) with y Switch x's and y's, so put x where y is and x where y is. Solve for y Replace y with f^-1(x)
Take the integral: integral \[\int\limits(7 x-13) dx \] Integrate the sum term by term and factor out constants: \[ = 7 \int\limits x d x-13 \int\limits 1 d x \] The integral of x is x^2/2: \[= (7 x^2)/2-13 \int\limits 1 dx \] The integral of 1 is x: Answer: \[ = (7 x^2)/2-13 x+constant \]
Ignore that first random "integral"
Integration...why?
He's looking for inverse, not area.
Because that was the most simple way of answering this question.. Holy crap. I completely misunderstood this question.
Hahahaaaa
I wasted so much time on that -.-
\[f(x) = 7x-13 ~~~ \implies y = 7x-13\] \[x = 7y-13 \] Solve for y now \[y = \frac{ x+13 }{ 7 } \implies f ^{-1}(x) = \frac{ x+13 }{ 7 }\]
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