Question

4^2x = 32^1/2
Solve for x.

Answer 1

same as before... use a base of 2

\[(2^2)^{2x} = (2^5)^{\frac{1}{2}}\]

Answer 2

\[4^{2x}=32^{1/2}\]

\[32^{1/2} = \sqrt{32} = 4\sqrt{2}\]

\[2x = \frac{ \log(4\sqrt{2)} }{ \log(4) } \]

just divide by 2 now.

Answer 3

use the index laws... to simplify the powers

and now they are the same base... just equate the powers

Answer 4

Thanks so much you guys! That was much simpler than how my teacher explained it. :)