write a polynomial function with given roots :- 3+i , 2 and -4
This will be a fourth degree polynomial. One root is (x - 2), another is (x + 4) another is (x - (3 + i)) and because you have a - (3 + i), you also have to have a + (3 + i).
So here they are, all in a row!
ok
(x - 2)(x + 4)(x - [3 + i])(x + [3 + i])
if \(a+bi\) is a root, so is \(a-bi\)
Otherwise, the function would not have real coefficients
Unless this is supposed to be a complex polynomial
ahh.........i get it
So let's multiply those out, 2 sets of parenthesis at a time. Let's work with the first 2, becasue they do not have the imaginary i in them.
uhh wait
(x - 2)(x + 4) =\[x ^{2}+2x-8\]
x^2+2x-8
ok gotcha......next thing?
wait for what? O right! That's right, you got it! Now let'ss do the others.
|dw:1404425386083:dw|
Join our real-time social learning platform and learn together with your friends!