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Mathematics 15 Online
OpenStudy (anonymous):

WILL AWARD MEDAL AND FAN! Can someone please explain step by step how to solve this? This is using double and half angle identities. For some reason i am getting the wrong answer for this...

OpenStudy (anonymous):

OpenStudy (anonymous):

first you need to know that \(\cos(A)=\frac{12}{13}\)

OpenStudy (anonymous):

then use the half angle formula

OpenStudy (anonymous):

Ok i did that and got it wrong

OpenStudy (anonymous):

did you write \[\sin(\frac{A}{2})=\sqrt{\frac{1-\frac{12}{13}}{2}}\]?

OpenStudy (anonymous):

yes but because it is in quadrant 1 i wrote 1 + 12/13

OpenStudy (anonymous):

no

OpenStudy (anonymous):

half angle formula for sine has a minus sign inside the radical for cosine it is plus

OpenStudy (anonymous):

So its not 1+ 12/13 for the numerator?

OpenStudy (anonymous):

no that is for the half angle formula for cosine

OpenStudy (anonymous):

the fact that it is in quadrant one tells you two things first that \[\cos(A)=\frac{12}{13}\] and second that it is the positive square root, not the negative one

OpenStudy (anonymous):

but the half angle formula for sine is \[\sin(A)=\sqrt{\frac{1-\cos(A)}{2}}\]

OpenStudy (anonymous):

so is the answer 1/sqrt26? i feel like i did that wrong...

OpenStudy (anonymous):

???

OpenStudy (anonymous):

never mind thanks my answer is correct!

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