WILL AWARD MEDAL AND FAN! Can someone please explain step by step how to solve this? This is using double and half angle identities. For some reason i am getting the wrong answer for this...
first you need to know that \(\cos(A)=\frac{12}{13}\)
then use the half angle formula
Ok i did that and got it wrong
did you write \[\sin(\frac{A}{2})=\sqrt{\frac{1-\frac{12}{13}}{2}}\]?
yes but because it is in quadrant 1 i wrote 1 + 12/13
no
half angle formula for sine has a minus sign inside the radical for cosine it is plus
So its not 1+ 12/13 for the numerator?
no that is for the half angle formula for cosine
the fact that it is in quadrant one tells you two things first that \[\cos(A)=\frac{12}{13}\] and second that it is the positive square root, not the negative one
but the half angle formula for sine is \[\sin(A)=\sqrt{\frac{1-\cos(A)}{2}}\]
so is the answer 1/sqrt26? i feel like i did that wrong...
???
never mind thanks my answer is correct!
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