If cos Θ = negative two over five and tan Θ > 0, what is the value of sin Θ?
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OpenStudy (anonymous):
Use \[
\cos^2\theta+\sin^2\theta = 1
\]
OpenStudy (anonymous):
That will give you the absolute value. The part about \(\tan\theta >0\) it just to let you know which quadrants it is in.
OpenStudy (anonymous):
???
OpenStudy (anonymous):
I know it is not "Square Root of 21 over 5"
OpenStudy (anonymous):
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OpenStudy (anonymous):
there is a picture of an angle with cosine \(\frac{2}{5}\)
you are missing the sine, which you do by finding the missing side via pythagoras
OpenStudy (anonymous):
It is -2/5
OpenStudy (anonymous):
The Cosine
OpenStudy (anonymous):
@satellite73
OpenStudy (anonymous):
@satellite73???
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OpenStudy (anonymous):
Hello?
OpenStudy (anonymous):
did you find the length of the missing side?
OpenStudy (anonymous):
No, the cosine is -2/5
OpenStudy (anonymous):
You gave me an angle for 2/5
OpenStudy (anonymous):
fine
you still need the length of the missing side
i am not interested in whether it is positive or negative at the moment because i cannot draw a triangle with one side negative length
we can worry about the sign of the answer later
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OpenStudy (anonymous):
then the sin should equal The Square Root Of 29, negative or not.
OpenStudy (anonymous):
no
OpenStudy (anonymous):
Correct?
OpenStudy (anonymous):
not even close
OpenStudy (anonymous):
Oh
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OpenStudy (anonymous):
use pythagoras to find the missing side
it is not \(\sqrt{29}\) for sure
OpenStudy (anonymous):
hint, it is a side, not the hypotenuse
OpenStudy (anonymous):
ohhh!
OpenStudy (anonymous):
what do you get for the side?
OpenStudy (anonymous):
the square root of 21
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OpenStudy (anonymous):
right
and that is not the sine, that is just the length of the side
the sine is the opposite over the hypotenuse
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
that makes your answer
\[-\frac{\sqrt{21}}{5}\]
OpenStudy (anonymous):
i will let you figure out why it has to be negative
OpenStudy (anonymous):
Thank you so much!
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