The resistance (R) in a wire increases when the length of the wire (L) increases. Write the correct equation for this scenario, and solve for when the length is 1. Length Resistance 10 2 15 3 R = 20 / L; R = 20 R = .2L; R = 5 R = .2L; R = .2 R = 20 / L; R = 5
@Whitemonsterbunny17
"Resistance (R) in a wire increases when the length of the wire (L) increases" implies R is proportional to L . That is, R = k * L where k is a constant. It is given that when L = 10, R = 2. Substitute these values and find k.
ok i got B
R = k * L -- (1) When L = 10, R = 2 2 = k * 10 find 'k' Then they ask for R when L = 1. Put the k value you find and L = 1 in equation (1) and find R.
ohhhh ok nevermind its A
thank you really do appreciate it
That is not the correct answer.
what? if its not A then it has to be D
R = k * L -- (1) When L = 10, R = 2. Substitute. 2 = k * 10 divide by 10 2/10 = k k = 0.2 R = 0.2L when L = 1, R = 0.2 * 1 = 0.2 Answer: R = 0.2L and R = 0.2
wow im stupid. i get it now. thanks for explainging it
yw.
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