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Mathematics 20 Online
OpenStudy (anonymous):

Rate of Change Formula and explanation, please?

OpenStudy (anonymous):

Instantaneous or average rate of change?

OpenStudy (anonymous):

Average.

OpenStudy (anonymous):

An example that I could work out would probably help.

OpenStudy (anonymous):

The average rate of change is simply the slope formula.... Example If a start my car at point A and drive 60 miles in 30 minutes what would be am average rate of change... t(1) = 0 for starting time....d(1) = 0 for starting point. t(2) = 30 for ending time d(2) = 60 for ending distance \[Rate of change = ....\frac{ d1-d2 }{ t1-t2} = Rate of change per minute\]

OpenStudy (anonymous):

Okay, that makes sense.

OpenStudy (anonymous):

Instantaneous is somewhat different

OpenStudy (anonymous):

So, when doing the average, can D be x or y?

OpenStudy (anonymous):

I'm trying to find the average Rate of Change using x and y.

OpenStudy (anonymous):

In his example, t would be x and d would be y. The variables are interchangable; you could use whatever variables you'd like.

OpenStudy (anonymous):

Oh, okay.

OpenStudy (anonymous):

And just to make sure, the D1 and D2, for example, have the 1 and 2 to show which variable or number is to be used, rather than saying D1 = 0 x 1. Is that correct?

OpenStudy (anonymous):

Erm, wait...the slope formula was more like D2 - D1 over T2 - T1. Was the change accidental, or is that how it is for Average Rate of Change?

OpenStudy (anonymous):

Average rate of change is the slope.

OpenStudy (anonymous):

Yes, which would be D2 - D1, etc., rather than D1 - D2, right?

OpenStudy (aum):

Average rate of change of f(x) in the interval \([x_1,x_2]\) is: \(\Large \frac {f(x_2) - f(x_1)}{x_2-x_1} \)

OpenStudy (anonymous):

D2-D1 is fine as long as it is T2-T1 as the denominator. It can be D1-D2 as long as it is T1-T2 as the denoinator

OpenStudy (anonymous):

But wouldn't it give different answers if you did it as either way?

OpenStudy (anonymous):

As in, if you went for: |dw:1404441518403:dw| wouldn't the results be different?

OpenStudy (aum):

\(\Large \frac {a-b}{c - d} = \frac {b-a}{d-c} \) Its is equivalent to multiplying both top and bottom by -1 which will not change the result.

OpenStudy (anonymous):

Can I have an example used for Average Rate of Change? I feel like I'd understand it better that way.

OpenStudy (aum):

Let f(x) = 3x^2 Find the average rate of change of f(x) between x = 1 and x = 4. Will this example work for you? Or do you need something else?

OpenStudy (anonymous):

Well, what I mean is, can we take the example, and go through the steps together? Through text like: -3 - 3 over -2 - 2 -6 over -4 1.5 or through drawings?

OpenStudy (aum):

f(x) = 3x^2 Find the average rate of change of f(x) between x = 1 and x = 4. When x = 1, f(x) = 3*1^2 = 3 When x = 4, f(x) = 3*4^2 = 48 x f(x) 1 3 4 48 Average rate of change = (48 - 3) / (4 - 1) = 45 / 3 = 15 or Average rate of change = (3 - 48) / (1 - 4) = -45 / -3 = 15

OpenStudy (anonymous):

Oh, huh. I think I managed to use the Average Rate of Change for the original problem I had, and I see what you guys meant when you said it wouldn't change.

OpenStudy (anonymous):

Okay, now that's a lot different, but maybe closer to what the problem is actually asking of me. I guess I'll show what the problem is so we can pinpoint what exactly I'm supposed to do.

OpenStudy (anonymous):

Part C: What is an approximate average rate of change of the graph from x = 2 to x = 5, and what does this rate represent? (3 points)

OpenStudy (aum):

From the graph, when x = 2, what is the y value? From the graph, when x = 5, what is the y value?

OpenStudy (anonymous):

This was what I got: 1. Y2 - Y1 over X2 - X1. 2. 160 - 100 over 5 - 2. 3. 60 over 3. 4. 20. So, the Average Rate of Change is 20. Y1 - Y2 over X1 - X2. 100 - 160 over 2 - 5. -60 over -3. 20.

OpenStudy (aum):

Correct.

OpenStudy (anonymous):

Thank you, then! And I mean to all of you who responded. I have another question that I need help with, but I'm going to post it in a new question.

OpenStudy (aum):

You are welcome.

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