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Chemistry 24 Online
OpenStudy (raffle_snaffle):

The volume of a single molecule of water is 2.99x10^-23 mL. For a sample of gaseous water at 1.00 atm and 150 *C, what fraction of the container's volume is occupied by the molecules themselves?

OpenStudy (raffle_snaffle):

@Abhisar

OpenStudy (raffle_snaffle):

@nincompoop

OpenStudy (nincompoop):

formula

OpenStudy (nincompoop):

nope

OpenStudy (nincompoop):

try pv=nrt

OpenStudy (raffle_snaffle):

i said pv=nrt lol

OpenStudy (nincompoop):

oh laughing out loud

OpenStudy (raffle_snaffle):

so do we need mols?

OpenStudy (raffle_snaffle):

wait a min...

OpenStudy (nincompoop):

1 mole H2O = 18.0 g = 18.0 mL 1 mole H2O = 6.022x10^23 molecules 6.022x10^23 molecules x 2.99x10^-23 mL

OpenStudy (nincompoop):

V = nRT/P = 1 mole x 0.0821 x 423.15 / 1.00 atm

OpenStudy (raffle_snaffle):

um that isn't one of the choices. This is a multiple choice question

OpenStudy (nincompoop):

uh I didn't give you the answer these are the solutions laughing out loud

OpenStudy (raffle_snaffle):

1 mol H2O = 18 g = 18 mL ?

OpenStudy (nincompoop):

ya

OpenStudy (nincompoop):

mL = g

OpenStudy (nincompoop):

you can prove it using volume, density and mass

OpenStudy (raffle_snaffle):

I am doubting this because I was taking grams of a solution today and it didn't equal the same as mL

OpenStudy (nincompoop):

how? displacement?

OpenStudy (raffle_snaffle):

well since mL=g I can find the mols of H2O and then apply the pv=nrt equation

OpenStudy (nincompoop):

yes

OpenStudy (raffle_snaffle):

okay thanks. Are yo familiar with oxidation reduction?

OpenStudy (nincompoop):

yes

OpenStudy (nincompoop):

read up though, because it gets a little complicated

OpenStudy (raffle_snaffle):

i can find the O.N. and determine which compound is the OA or RA, but I can't or have a hard time balancing the equation

OpenStudy (nincompoop):

? what are those?

OpenStudy (nincompoop):

oxidation number?

OpenStudy (raffle_snaffle):

yeah oxidation number

OpenStudy (nincompoop):

redox is taught in gen chem, there's no need for ochem for it and yes I am taking ochem

OpenStudy (raffle_snaffle):

oh i thought they taught redox in o chem

OpenStudy (nincompoop):

it's the same principle and rule of thumb

OpenStudy (nincompoop):

no redox is fundamental in acids and bases, electrolytes, and half-reaction to galvanic cells (battery)

OpenStudy (raffle_snaffle):

my final answer is 5.76x10^-23

OpenStudy (nincompoop):

are you in ochem? because the question you asked is not ochem related

OpenStudy (raffle_snaffle):

no gen chem2

OpenStudy (nincompoop):

did you divide mL by 1000 to convert to liter?

OpenStudy (raffle_snaffle):

no... no i didn't lol

OpenStudy (raffle_snaffle):

5.76x10^-26

OpenStudy (nincompoop):

that is fine, as long as you are consistent with units 18.0 mL / 3.472x10^4 mL

OpenStudy (raffle_snaffle):

can you help me with one more question

OpenStudy (nincompoop):

do you understand what is going on though?

OpenStudy (raffle_snaffle):

Mercury is 13.6 times as dense as liquid water. What would be the reading of a water-filled barometer at normal atmospheric pressure, 760. mmHg?

OpenStudy (raffle_snaffle):

I need to use the same units.

OpenStudy (raffle_snaffle):

L=g and mL=mg

OpenStudy (nincompoop):

well not only that, I mean how to approach the question

OpenStudy (nincompoop):

http://www.chemteam.info/Solutions/Mole-Fraction.html

OpenStudy (raffle_snaffle):

I knew I was suppose to use pv=nrt, but I was having a hard time figuring out how to obtain mols of H2O. I didn't know the L=g

OpenStudy (nincompoop):

it is another way of calculating concentration

OpenStudy (raffle_snaffle):

Okay I can barely keep my eyes open... thanks for you rhelp

OpenStudy (raffle_snaffle):

I will work out the other question later

OpenStudy (kanwal32):

@nincompoop @raffle_snaffle pls help http://openstudy.com/study#/updates/53b659d9e4b072c759d926f0

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