Question

How would I find the foci of this graph?

Answer 1

Seems like you have an ellipse.
Formula for Foci of an Ellipse:
\[\frac{ (x-h)^2 }{ a^2 }+\frac{ (y-k)^2 }{ b^2 }=1\]
a = horizontal radius
b = vertical radius
h and k corresponde to the center points
as x and y to any point on the ellipse.

Answer 2

You can also use:
\[F = \sqrt{a^2+b^2}\]
a = horizontal radius
b = vertical radius

to find the distance of the focus points.

Answer 3

FOCI are max horizontal distance from centre..so you can observ it by grpah easily..

Answer 4

so would it be (-5,0) and (5,0) ?

Answer 5

Oh yay, thanks :)

Answer 6

^because you were being inappropriate

Answer 7

Foci = \((\pm c, 0)\)

\(c = \sqrt{a^2-b^2}\)

Answer 8

did u find the value of \(c\) ?

Answer 9

I have a question, how would i find the horizontal radius and the vertical radius? Is that like (0,3) (0,-3) and (-5,0) (0,5)?

Answer 10

take half of major axis

Answer 11

major axis = 5--5 = 10

so horizontal radius = 10/2 = 5

Answer 12

and then vertical radius would be 3?

Answer 13

I plugged that in and got like 5.830... now what would i do?

Answer 14

I apologize for asking so much, it's just that I'm homeschooled and have trouble learning maths.

Answer 15

Hey c:
Where we stuck at?
Trying to find the coordinates of the focus?
I'm a little worried because Zaibali's response doesn't look right....