Can anyone explain dividing polynomials? Pleeaasseee :(
The long way or using synthetic division?
Ummm well what's that? :/
is there a certain way that you HAVE to know how to use? Or are you just wanting to divide and get the job done? I can teach you either way
Whichever would be the quickest and easiest way.
The easy way or the more difficult way?
Ok, then synthetic is definitely the way to go. Do you have a polynomial you are wanting to divide by another polynomial, or something? Depending upon what your divisor is, you may not be able to use synthetic. Show me what you need to divide out.
Okay so I guess we'll just start with an easy one and go from there, what if we had (12a^5b^3)/(8ab^2)
Do you mean this:
\[\frac{ 12a ^{5}b ^{3} }{ 8ab ^{2} }\]
Yeah :)
Ok, you don't need synthetic here because you are not dividing a polynomial by a binomial. this is a case of pure simplification.
Okay
First reduce between the 12 and the 8. 8 doesn't go into 12 evenly, but they are both even numbers so they can be divided by 2 down til they can't be reduced any further. 12 reduces to 6 which reduces to 3 which cannot be reduced any further. 8 can be reduced to 4 which can be reduced to 2 which cannot be reduced any further, so the numbers part looks like this now:
\[\frac{ 3a ^{5}b ^{3} }{ 2ab ^{2} }\]
Right! So first simplify everything, gotcha.
Then reduce between the a on the top and the a on the bottom. There is one on the bottom of the fraction, so that one would cancel out and take 1 in the top with it when it goes. So now you have:\[\frac{ 3a ^{4} b ^{3}}{ 2b ^{2} }\]
Now reduce between the b on the top and the b on the bottom. You have a b squared on the bottom and a b cubed on the top. The basic rule for exponents is that you subtract the power of b in the bottom from the power of b on the top, like this:
\[b ^{3}-b ^{2}=b ^{3-2}=b ^{1}=b\]
So now the b's in the bottom are gone and you have one left on top. So that whole thing reduces to \[\frac{ 3a ^{4} b}{ 2 }\]
That's more simplification than division.
and it can't be simplified further, so we're done?
Yes, that's correct @LearningIsAwesome
So then if instead we had, let's say, \[12b^2/3b\]
Same old, same old.. \(\dfrac{12b^2}{3b}\)
First we divide the numbers, so it's \[4b^2/b\]
then the variable, making it 4b, because of the understood exponent of 1?
3 can get into 12..so we have: \(\dfrac{4b^2}{b}\) Now for the variables: \(b^2 - b^1 \rightarrow b^{2-1} \rightarrow b^1 \rightarrow b\)
Yes, you got it.
Which leaves us with..?
4b
Yes. :)
Awesome! So, what would be the next step in learning how to divide any polynomials? @iGreen What would be something just a little more complicated?
Dividing a trinomial by a binomial is a long ..
Can you give an example? I can make another question for ya and tag you on it so you can get all them medals haha
Okay, sure.
Join our real-time social learning platform and learn together with your friends!