Question

if gas in a sealed container has a pressure of 50kpa at 300k what will the pressure be if the tempature rises to 360k

Answer 1

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Answer 2

By combined gas law PV=nRT we get that
\(\huge P\propto T\)
So,
\(\huge\frac{P_1}{P_2} = \frac{T_1}{T_2}\)

Answer 3

Therefore, \(\huge\frac{50}{P_2}=\frac{300}{360}\)
P\(_2\)=60KPa