Solve each equation for x. Convert to an exponential equation. Simplify and solve the equation to find the solution. 5=log_3(x^2+18) 2=log(3x+4)
For number 1, We can raise each side to the power 3 \[\large 5 = log_3(x^2 + 18)\] \[\large 3^5 = 3^{log_3(x^2 + 18)}\] Now remember that \(\large 3^{(log_3(x))} = x\) so we have \[\large 3^5 = x^2 + 18\] \[\large 243 = x^2 + 18\] \[\large x^2 = 225\] \[\large x = \pm 15\] Did that make sense?
Yeah thank you!
No problem, and you can use basically the same thing for question 2, however if there is no base of the log, we use the power 10
Kkay and for the first one 3^(log_3(x)) = x is the exponential equation right
Well THAT is a way of simplifying logarithms. The actual exponential equation came from that \[\large 3^5 = 3^{log_3(x^2 + 18)}\]
Ohh alright thanks
could you help me on another one? I'm about to post it..
Sure :)
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