Question

If someone helps me ill fan and medal them... please help

Answer 1

Is it supposed to look like this:
\[\frac{ 3x+6 }{ 8 }=\frac{ 7x-1 }{ 6 }\]

Answer 2

Okay,good.

Answer 3

Here, solve this: \[\frac{ 3*1+6 }{ 8 } = \frac{ 7*1-1 }{ 6 }\] Then tell me whether or not it's true.

Answer 4

Yes. Obviously, that's not true, so you can rule out x=1

Answer 5

The answer can be found by multiplying both sides by two:
\[\frac{ 3x+6 }{ 4 }=\frac{ 7x-1 }{ 3 }\]

Answer 6

Now cross multiply in order to get to this equation:
\[3(3x+6)=4(7x-1)\]

Answer 7

Max made it to this step, then he distributed the 3 on the left and the 4 on the right:
\[9x+18=28x-4\]

Answer 8

would have distributed*

Answer 9

Now, do you see the difference between our answer and Max's answer?

Answer 10

Ours:\[9x+18=28x-4\]
Max's:\[9x+18=28x-1\]

Answer 11

Can you handle it from here?

Answer 12

Max forgot to multiply 4*1 when we cross multiplied, and he just brought the 1 down from the numerator instead.

Answer 13

Or wait, not when we cross multiplied. He forgot to do that when we distributed and brought the 1 down from our cross multiplication.