Question

Mercury is 13.6 times as dense as liquid water. What would be the reading of a water-filled barometer at normal atmospheric pressure, 760. mmHg?

Answer 1

@Abhisar

Answer 2

What do u think ?

Answer 3

I hate just randomly guessing which formula to use.

Answer 4

hmmmm

Answer 5

Do we use PV=nRT, P being 1 atm, then we can solve for n or find n by looking at the periodic table

Answer 6

or do we need an equation with density in it? like for example m/v=MP/RT

Answer 7

actually m not sure about this one. I think @somy will help u better

Answer 8

oh okay.

Answer 9

were not interested in using the temperature, we're only making a comparison of the volumes between the two liquids at a certain pressure.

We can use the definition of density: \(\sf \rho=\dfrac{m}{V}\)

The atmospheric pressure will equal masses of both of the liquids up the tube in the barometer (which will give us our reading). Can you think of how to do this now?

Answer 10

"The atmospheric pressure will push** equal.."

Answer 11

1 atm=760mmHg=760 tor
Three factors affect the pressure in a fluid:
The depth the pressure is measured at
The density of the fluid
The gravitational field strength
P=dgh
760=1*10*h
h=76

Answer 12

so you're saying that the reading will be 76 mm? 1 tenth of that of mercury?

Answer 13

yes

Answer 14

that's impossible, mercury is much denser than water. The same mass needs to be raised.

Answer 15

H1/H2=D2/D1
Density of wate is 1.00g/ml
Height of H2O/Height of Hg=Density Of Hg/Density of H2O
13.6(g/ml)*760mm/1.00(g/ml)

Answer 16

yeah, i think that's right.