Find the derivative of
\[\huge y=\sqrt{\sin \sqrt{x}}\]
@ganeshie8
chainz :>
yea i know that is chain rule
obviously but i have to apply it here @tkhunny
Sure you do. What's this \(\dfrac{d}{dx}\sqrt{x} =\;\)??
Okay...somehow, you have to pinpoint what I like to call the outer shell function :) The function... that covers all the others...
I think THIS part of the function looks like a shell... don't you? :) \[\Large \color{red}{\sqrt{\color{black}{\sin \sqrt x}}}\]
yes
Well, here's how it works... just differentiate the 'shell' as if whatever's inside is just a big fancy x...first.... now, what is the derivative of 'square root'? ^^
of root x ?
yeah, that...
1/2root x
Okay, so the first piece is \(\dfrac{1}{2\sqrt{sin(\sqrt{x})}}\). What's next?
^okay, as much as I'd like to say that's it, that's not it :D After you differentiate the 'outer shell', you then multiply that entire expression by the derivative of WHATEVER WAS INSIDE that shell thingy... So inside the outermost radical is a \(\large \sin \sqrt x\) So what's the derivative of that? (lawlz chain rule again)
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