Question

Lead has a molar heat capacity of 26.4 J/K•mol. What molar enthalpy change occurs when lead is cooled from 302°C to 275°C.

Answer 1

\(\Delta H=C_p*\Delta T\)

Answer 2

Initial Temp = 302°C
Final Temp = 275°C
C = 37.4J/K•mol
Change the °C into Kelvin. By adding the value °C to 273
∆H = C∆T
37.4J/K•mol*(548-575)

Answer 3

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