Question

use the discriminant to find the number of real solutions of the following quadratic equation: 2x^2+2x+2=0

Answer 1

First step: Divide throughout by 2 to simplify.

Answer 2

just put your a ,b and c in the form\[\pm\sqrt{b^{2}-4ac}\] and then use the table in the link
http://www.mathwarehouse.com/quadratic/discriminant-in-quadratic-equation.php

Answer 3

x^2+x+1=0

Answer 4

Yes. Compare x^2+x+1=0 to ax^2 + bx + c = 0 and identify a, b and c.

Then find the discriminant b^2 - 4ac.

If the discriminant < 0, no real solutions
If the discriminant = 0, one real solution (twice)
If the discriminant > 0, two real solutions