A baker needs between 40lb and 50lb of flour-sugar mixture that contains ten timesas much flour as sugar. What are the possible weights of flour the baker can use?
just transform these words into variable between equals 40>and 50< sugar equals S and flour equals F (has the same weight) F = x S= x \[50>10(x+x) > 40 \] and solve it
ten times as much flour as sugar that means you have lots more flour than sugar. if you have S lbs of sugar, you will have 10*S or 10 S pounds of flour all together you would have 10 S pounds of flour and S lbs of sugar, or 10 S + S pounds total (which adds up to a number between 40 and 50) 11 S pounds I would look for a number so that 11 divides evenly into it. Example: 44 pounds 11 S = 44 S= 4 pounds that is how much sugar you have. How much flour would you have ?
i thought of it like that, but i wasn't sure what is that exact means and i get it 10 to be easily cancelled with 50 and 40 :P
You really want to divide by 11 (see the above post) if you expect an integer solution. For example, if we pick a number between 40 and 50 that can be evenly divided by 11, we would pick 44. the amount of sugar would be 44/11 = 4 pounds the amount of flour would be 10 times more, i.e. 10*4= 40 and notice 40 pounds of flour + 4 pounds of sugar = 44 pounds of flour and sugar
OK thanks
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