Question

solve the following equation using the substitution 2^x=u
2^x+2^2-x=5
(4^x)-3(2^x)=10
2^(2x+1)-11(2^x)+15=0

Answer 1

nope 2^x

Answer 2

take your time these are three seperate equation

Answer 3

We need to say somehow that u^2+something-u=5 so we can solve for u and then substitute 2^x in the answer to get our solution...

Answer 4

Square each term in the equation maybe.

Answer 5

\[2^x + 2^{2-x}=5\]Write it something like this:\[2^x + \dfrac{2^2}{2^x}=5\]It should be clearer now.

Answer 6

@Abmon98

Answer 7

just plug in 2^x = u and you will see a quadratic in u