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Algebra 15 Online
OpenStudy (anonymous):

Jake has proved that a function, f(x), is a geometric sequence. How did he prove that? He showed that an explicit formula could be created. He showed that a recursive formula could be created. He showed that f(n) ÷ f(n - 1) was a constant ratio. He showed that f(n) - f(n - 1) was a constant difference. I don't get this at all how can this be a geometric sequence? please help

OpenStudy (anonymous):

@dan815

OpenStudy (anonymous):

@sammixboo

OpenStudy (anonymous):

@kropot72

OpenStudy (anonymous):

@iambatman

OpenStudy (anonymous):

@vzfreakz

OpenStudy (anonymous):

What could we eliminate?

OpenStudy (anonymous):

um D?

OpenStudy (anonymous):

Correct and what else?

OpenStudy (anonymous):

C

OpenStudy (anonymous):

LEt's keep C for now.

OpenStudy (anonymous):

Do you need explaining or?

OpenStudy (anonymous):

ok so i don't know what else to eliminate but i think maybe i should eliminate A

OpenStudy (anonymous):

Yes

OpenStudy (anonymous):

@vzfreakz

OpenStudy (anonymous):

Close this question.

OpenStudy (anonymous):

Remember: f(n)=arn−1,n∈Z+ He showed that f(n) ÷ f(n - 1) was a constant ratio.

OpenStudy (anonymous):

where did the arn come from

OpenStudy (anonymous):

thank you btw

OpenStudy (anonymous):

its not letting me close it

OpenStudy (anonymous):

its closed @vzfreakz

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