Question

Let f(x) = x2 - 8x + 5. Find f(-1).

Answer 1

just sub x=-1 and then use order of operation

Answer 2

I did but I kept getting the same answer, 11

Answer 3

\[f(-1)=x^2-8x+5\]

Answer 4

Subtract -5 to both sides of the equation.

Answer 5

We went over a similar question like this, I suggest you go over all of them again, before you post another question.

Answer 6

I've tried the questions over and over but I kept getting the same answer but it's not part of my answer choices

Answer 7

Mhm alright, can you show me how you would set up f(-1) I want to see what exactly you're doing wrong.

Answer 8

Do you have a fraction as an answer choice?

Answer 9

No I got the answer batman , what I did was instead of 1 I inserted -2 for the -1^2

Answer 10

Ah lol, yeah that happens sometimes, we accidentally sub in the wrong number, because we're thinking of one thing and then another at the same time XD. Glad you figured out your mistake :)

Answer 11

why to subtract -5 @vzfreakz ? :)

Answer 12

No you don't subtract -5 you add 5

Answer 13

\[f(x) = x^2-8x+5, ~~~ f(1) \implies (-1)^2-8(-1)+5\]

Answer 14

i must say thats very clever :) but the question is not about evaluating the function at x = -1 as precal suggested earlier

Answer 15

thats for Lydian ^

Answer 16

f(-1) lol

Answer 17

typo *

i must say thats very clever :) but the question is about evaluating the function at x = -1 as precal suggested earlier

Answer 18

I had gotten the answer correct, however I tried two on my own without asking without any assistance and I was sure they were correct, it was on the answer choice..I got them wrong two wrong out of ten @iambatman @ganeshie8 ;(

Answer 19

@LydiannAquino The focus is more the process. We are happy to help you but we are interested in you learning the process and concept. Because as you advance in the study of mathematics, it gets harder to do problems when a student lacks the basic skills and process.

Answer 20

That is true but, I feel like I understand but then it turns out I don't according to the results doing it on my own, but then when I do it in collaboration I completely comprehend. ;/ @precal

Answer 21

Well we all have our own road in mathematics. There is no "Royal Road" to any mathematics. I believe this was once told to a real princess by her royal tutor when she studied geometry. We all have our own journey. I wish you well on your journey.

Answer 22

Thankyou @precal