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Mathematics 21 Online
OpenStudy (anonymous):

cos(19pi/12) how would you find the exact value of this?

OpenStudy (anonymous):

http://openstudy.com/study#/updates/51c3bd95e4b069eb00c4dbb3 I was looking at that, but I don't understand the half formula.

OpenStudy (anonymous):

@precal can you help me understand it please?

OpenStudy (abb0t):

@tHe_FiZiCx99

OpenStudy (anonymous):

@abb0t thank you for the help :)

OpenStudy (the_fizicx99):

._.

OpenStudy (abb0t):

You're very welcome, @lolabieber make sure to fan + medal those who help.

OpenStudy (anonymous):

Alright :)

OpenStudy (precal):

cos(285 degrees)

OpenStudy (precal):

do you have to use a particular method?

OpenStudy (anonymous):

Yes I have formulas and the unit circle

OpenStudy (precal):

ok but are you suppose to use sum and difference? btw do you know how to convert it into degrees?

OpenStudy (anonymous):

Yes those the sum and difference of tan, sin, or cos And no I don't

OpenStudy (anonymous):

I do if the radian is on the unit circle, but not if it's not

OpenStudy (precal):

ok real quick pi is 180 degrees so (19 times 180)=3420 divide that by 12 and you get 285 degrees

OpenStudy (precal):

On the unit circle, 285 degrees is not listed so we have to find 2 angles that we know see if you can find two angles that you can add or subtract to create 285 degrees

OpenStudy (anonymous):

\[\cos \frac{ 19 \pi }{ 12 }=\cos \left( \pi+\frac{ 7 \pi }{ 12} \right)=-\cos \frac{ 7 \pi }{ 12 }=-\cos \left( \frac{ 4 \pi+3 \pi }{ 12 } \right)\] \[=-\cos \left( \frac{ \pi }{ 3 } +\frac{ \pi }{ 4 }\right)=?\]

OpenStudy (anonymous):

so in order to convert it into degrees you always multiply by 180?

OpenStudy (precal):

no pi is 180 degrees

OpenStudy (precal):

|dw:1404609537005:dw|

OpenStudy (precal):

|dw:1404609550081:dw|

OpenStudy (anonymous):

yes but why did you multiply it

OpenStudy (precal):

|dw:1404609609178:dw|

OpenStudy (anonymous):

i think i get it a bit because its asking for 19 pis right? instead of just 1 pi?

OpenStudy (precal):

|dw:1404609654307:dw|

OpenStudy (precal):

all I really did was substitute the fact that pi is 180 degrees into the fraction and converted radians to degrees

OpenStudy (precal):

no can you find two numbers from the unit circle that will give me 285 degrees

OpenStudy (anonymous):

so it's between 3pi/2 and 5pi/3 so can one of them be 4pi/3

OpenStudy (precal):

@surjithayer is using a reference angle

OpenStudy (anonymous):

what do you mean?

OpenStudy (precal):

no you are looking for 200 + 85 or 180 + 105 or something like that you need to find two angles from your unit circle to create 285 degrees

OpenStudy (precal):

forget the reference angle approach, it seems you have not covered reference angles yet

OpenStudy (precal):

how about 330-45?

OpenStudy (anonymous):

11pi/6 and pi/4

OpenStudy (precal):

cos(330-45)=cos330cos45+sin330sin45

OpenStudy (precal):

yes rewrite it in terms of pi as you stated above

OpenStudy (precal):

then sub values and evaluate it

OpenStudy (anonymous):

so it's cos(11pi/6 -pi/4)=cos11pi/6*cos pi/4-sin11pi/6*sin pi/4

OpenStudy (precal):

yes

OpenStudy (anonymous):

okay im going to solve it give me a minute

OpenStudy (precal):

take your time

OpenStudy (anonymous):

im not getting it im getting 11pi^2/24 - 11pi^2/24 and that's 0

OpenStudy (precal):

I need to work it out, give me a moment

OpenStudy (anonymous):

okay

OpenStudy (precal):

cos(330-45)=cos330cos45+sin330sin45 \[\left( \frac{ \sqrt{3} }{ 2 } \right)\left( \frac{ \sqrt{2} }{ 2 } \right)+\left( \frac{ -1}{ 2 } \right)\left( \frac{ \sqrt{2} }{ 2 } \right)\]

OpenStudy (precal):

is this what you substituted into your formula?

OpenStudy (anonymous):

ohhhh okay I got confused wait let me try it again

OpenStudy (anonymous):

why'd you use sqrt2/2 ?

OpenStudy (anonymous):

never mind i figured it out

OpenStudy (anonymous):

i got sqrt6 -sqrt2 over 4

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