Question

How to rewrite the this as f(x)=mx+b

y+x+8=0

i wish i can get full procedure

Answer 1

so you need to isolate y from y+x+8=0

just subtract x+8 from both sides, and you will get 'y' on left side isolated.

Answer 2

can i see how should i do it?

Answer 3

let me give you an example, then you try this one :)

2x+y -12 =0
now i have to isolate 'y' , so i will subtract (2x-12) from both sides,
\(\Large 2x+y-12 -(2x-12) = 0-(2x-12) \\ \Large 2x-2x +y -12+12 = -2x+12 \\ \Large 0+y +0 =-2x+12 \\ \Large y = -2x+12\)

do the same procedure for y+x+8 =0
try it, if you make an error, we are her :)

Answer 4

here** lol

Answer 5

y+x+8=0
(-x+8) +y+x+8= 0-x+8
y=0-x+8
y=-x+8

how about this?
correct me if im wrong please thnx xD

Answer 6

just one error :
you subtracted -x+8

you should have subtracted -(x+8) or -x-8

Answer 7

how should i write it please help me

Answer 8

y+x+8=0
(-x-8) +y+x+8= 0-x-8
y=0-x-8
y=-x-8

thats it!

Answer 9

@shiqki017 are you aware of transposing terms?
Like bringing terms from L.H.S to R.H.S?

Answer 10

what do you mean sir?

Answer 11

y+x+8=0
So as @hartnn said.. you have to isolate 'y'....
So transpose r to the rhs!
RHS is the part to the right of the equation that is 0 in this case.
LHS is the part to the left of the equation that is (y+x+8) in this case.
While transposing or moving terms from the RHS to LHS or from the LHS to RHS, positives become negative and vice-versa.

So, here in this equation y+x+8=0
transpose x+8 from the LHS to RHS to isolate y on the LHS.
So, the equation becomes y=-x-8+0
which is y=-x-8.

If this is confusing, follow @hartnn's method. :)

Answer 12

@shiqki017 there is a typo in the third line *So transpose x+8 to the RHS. Sorry.