Question

X lim infinity 3x-1/x, how would I solve this limitation problem.

Answer 1

divide numerator and denominator by x
and use the fact that since x-> infinity, 1/x ->0

Answer 2

bdw, its
\(\dfrac{3x-1}{x}\)
right ?

Answer 3

<3

Answer 4

Another way to do it is using L'Hopital's Rule.

Answer 5

I just dropped a hint :P

Answer 6

\(=\dfrac{3x}{x} -\dfrac{1}{x} = 3- \dfrac{1}{x}\)

Answer 7

then you can plug in 1/x = 0