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prove that (A') = (A' U B)
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A-B = set of elements which are in A but not in B = A - (AnB) B-A = set of elements which are in B but not in A = B - (AnB). Therefore, (A-B) U (B-A) = (AUB) - (AnB) By drawing Venn Diagram, this can be established.
this is true only if there is no intersection between sets A and B (AB) = empty set then B would completely be in A' making it equal to the union of A' and B
In terms of a Venn diagram, |dw:1404672378610:dw| When A and B are disjoint (i.e. \(A\cap B=\emptyset \), then \(A'=A'\cup B\)
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