find (fog)(2) and (f+g)(2) when f(x)=1/xand g(x)=4x+9
So we need to find f(g(2)) and we also need to find f(2)+g(2)
do you know how to find g(2)?
do you plug in 2 for the g=4x+9?
you plug in x for 2 in the expression named g yes
so it equals 17?
g(2) is 17 that is right
so do you know how to find f(g(2)) you just found g(2) so you need to find f(g(2)) now f(g(2))=f(17) I replaced g(2) with 17 now you need to find f(17) f(g(2))=f(17)=?
so you plug in 17 where the f(x)=1/x right?
right
so f(g(2))=?
1/17?
right
now f(2)+g(2) you already found g(2) earlier you said it was 17 so we have now f(2)+g(2) f(2)+17
any clue what to do now?
\[\frac{ 1 }{ 17 }+\frac{ 17 }{ 1 }i am assuming\]
how did you get f(2) is 1/17? I think f(x)=1/x so f(2)=?
oh my apoligize so is it 1/2
yep great job now you need to simplify f(2)+g(2) f(2)+g(2) = 1/2+17
guess you could write that as a mix fraction
which basically it is already written that way
anyways lets summarize what we did we found f(g(2))=1/17 we also found f(2)+g(2)=17+1/2
so do we just plug in 2 where ever there is an x and then we just just combine f and g in (fog) or do we just leave it as (fog)(2) and do we just leave it as 1/2+17 for (f+g)(2)?
i didn't write 17+1/2 as a mix fraction i left that part for you we were asked to find (f o g)(2) which is f(g(2)) all you do first is take the g function and replace x's with 2's then take whatever result you get from that in plug into f which I believe we got 1/17 if i remember correctly by the way (g o f)(2) means g(f(2)) so you would start with f first if you seen this (f+g)(2) just means f(2)+g(2)
thank you :D
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