Factor 6x^4+15x^3-9x^2

Question

mathmate · Answer

Factor out the common factor 3x^2 and you're left with a quadratic which you probably know how to factor.

anonymous · Answer

Thanks

mathmate · Answer

You're welcome!  :)

anonymous · Answer

Factor 6x^4+15x^3-9x^2
3x^2(2x^4+5x-3)
x(3x+6)1(x-1)
?? can someone tell me what im doing wrong apparently 2x^4 is supposed to be 2x^2 and i dont know why as well

myininaya · Answer

so if you factor out 3x^2 divide each term inside the parenthesis by 3x^2
like so
$$3x^2(\frac{6x^4}{3x^2}+\frac{15x^3}{3x^2}-\frac{9x^2}{3x^2})$$
simplify each of the fractions there

anonymous · Answer

oh ok thanks, ill try it out in a bit

anonymous · Answer

i think im mixing concepts together from all the vids ive watched

mathmate · Answer

Did you get it yet? @5454354366464

anonymous · Answer

no :( after 3x^2(2x^2+5x-3)  dont u 2(-3) for product then keep the 5x as is
product = -6 and sum = 5

anonymous · Answer

so it would be 6 and -1 for something that multiples and adds

anonymous · Answer

(2x+6)(2x-1)
3x^2(x+3)(2x-1)
ok i got it thanks :D

mathmate · Answer

Yep, you got it!  Good job! :)