assume the procedure yields a binomial distribution with the trial repeated n times. use a binomial probabilities table to find the probability of x success given the probability of p success on a given trial(n=7,x=0,p=0.30)

Question

mathmate · Answer

$P(n,x,p)=nCx*p^x (1-p)^{n-x}$
so for n=7, x=0, p=0.3,
$P(7,0,0.3)=7C0*(0.3)^0 (0.7)^{7}=?$

anonymous · Answer

how would i calculate that in a texas instrument calculator.

mathmate · Answer

Sorry for not having supplied the formula.  :(
nCx = n! /(x!(n-x)!) 
where n! means factorial n, or n(n-1)(n-2)....(3)(2)(1). Note: 0!=1 by definition.
For your information, 7!=5040.
On texas Instruments calculator, it depends on the model.
Most scientific/graphics models have the n! function key.
Some even have the nCr and nPr keys.
If you are using the TI83,83+,84, graphics calculator, you would use the factorial key, nCr, or nPr key under math/prb and choices 2,3 or 4.