solve 2 log 3 x = 54
is it \[2\log_3(x)=54\]?
yea........ it is base 3
log 3(x) = 27.......?
thought so divide both sides by two and start with \[\log_3(x)=27\] then it should be fairly obvious
x = 9.....? my only doubt?
on no
ohh wait...
it is 3^27........?
\[\log_b(x)=y\iff b^y=x\]they are trying to trick you
yes, the answer is \(x=3^{27}\)
no don't fall for the trick!
but how come the answer is 7.6256.......... whereas 3^27 is a huge #
probably written in scientific notation let me check
ok
1) Divide both sides by 2 \[\log_{3} x=54/2\]\[\log_{3} x=27\]\[a=\log_{b} (b^a)\]\[\log_{3} x=\log_{3} (3^(27)\] x=3^27
how'd i guess? \[3^{27}=7.625597484987 × 10^{12}\]
yea but @Abmon98 ........by that we get 7625597........ and so on..... but the answer here is only 7.6256
scientific notation is being used
@satellite73 ............ hmm i see........ they didnt ask for scientific notation...... and the answer only states 7.6256........... that's it..... not even raised to something..... so i was wondering....??
i don't know what you mean by "the answer states"
ohh @satellite73 ....... i meant that answer only says 7.6256 and nothing like 7.6 x 10^12...............but dont worry....i got it.........bdw thx a lot for all the help..!!
I don't have the solution i've forgotten a lot but I know that when you multiply numbers you add the logs. 54 can be expressed as 2 *27 which is 2* 3^3 so it would be Log base 3 of 2 plus log base 3 of 3^3 3 log to base 3 of 3 = 3
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