Question

a missile is launched from the ground. its height, h(x), can be represented by a quadratic function in terms of time, x, in seconds. after 1 second, the missile is 110 feet in the air; after 2 seconds, it is 200 feet in the air. find the height, in feet, of the missile after 4 seconds in the air. help!

Answer 1

Let the height of the missile at time x be
\[h(x) = ax^2+bx+c\] which is quadratic in time.
h(0) = 0 (initially missile was at ground)
you can find c.
Then
h(1) = 110 ft =>a(1)^2+b(1)+c = 110 ft eqn 1
and similarly find
h(2) = 200 ft eqn 2
Solve eqn 1 and eqn 2 for a and b. Put them in h(x).

Answer 2

Then put x = 4 s and find h(4).

Answer 3

whats the final answer plz?

Answer 4

Can you work it out ?

Answer 5

nope

Answer 6

too lazy

Answer 7

OK. Can you find c the way I have described above ?

Answer 8

no

Answer 9

See, I won't give you final answer. We can work it out. For that you have to participate in the process. Read the steps I have listed above and try to find c.

Answer 10

not in the mood to do it man