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Mathematics 29 Online
OpenStudy (anonymous):

@IMStuck

OpenStudy (anonymous):

OpenStudy (dumbcow):

you get inverse by solving for "x" -- subtract the 1/2 over -- take sqrt -- subtract 3

OpenStudy (imstuck):

Inverse is also found by interchanging x and y, then solving the "new" equation for y. This is the inverse.

OpenStudy (imstuck):

change the x and the y:

OpenStudy (anonymous):

I got x=\[\sqrt{10y+8} -3\]

OpenStudy (imstuck):

\[5x+4=(y+3)^{2}+\frac{ 1 }{ 2 }\]Well, you're solving for y, so you shouldn't have an x = anything. You will have a y = something. K?

OpenStudy (imstuck):

Subtract the 1/2 from both sides to get:

OpenStudy (imstuck):

\[5x+4-\frac{ 1 }{ 2 }=(y+3)^{2}\]

OpenStudy (imstuck):

The do the math between the 4 and the 1/2 to get:

OpenStudy (imstuck):

\[5x+\frac{ 7 }{ 2 }=(y+3)^{2}\]

OpenStudy (imstuck):

Now take the square root of both sides to get:

OpenStudy (imstuck):

\[\sqrt{5x+\frac{ 7 }{ 2 }}=y+3\]

OpenStudy (imstuck):

Subtract the 3 from both sides to get the final answer of:

OpenStudy (imstuck):

\[-3\pm \sqrt{5x+\frac{ 7 }{ 2 }}=y\]Do you see that one there in your answer choices?

OpenStudy (anonymous):

yes, B . Thank you :)

OpenStudy (dumbcow):

lol thats essentially what i said

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